GO MATH! 1st grade Chapter 4 Review & Test (answer keys included)
2nd Street Sweets
136 Followers
Grade Levels
1st, Homeschool
Subjects
Resource Type
Standards
CCSS1.OA.A.1
CCSS1.OA.B.4
CCSS1.OA.C.5
CCSS1.OA.C.6
Formats Included
- PDF
Pages
11 pages
2nd Street Sweets
136 Followers
Also included in
This product is for 12 test reviews and 12 assessments for GO MATH! 1st Grade curriculum, Chapters 1-12. Answer keys provided for reviews AND assessments! These are great reviews and assessments for students who find the GO MATH! tests too challenging. They can be used as a study guide, group centerPrice $37.35Original Price $41.50Save $4.15
Description
This product is for one test review and one assessment for Chapter 4 of GO MATH! 1st Grade curriculum. Answer keys provided for review AND assessment!
This is a great review and assessment for students who find the GO MATH! test too challenging. I use it with my Special Education students who need an alternate assessment.
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Total Pages
11 pages
Answer Key
Included
Teaching Duration
N/A
Last updated Nov 21st, 2019
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Standards
to see state-specific standards (only available in the US).
CCSS1.OA.A.1
Use addition and subtraction within 20 to solve word problems involving situations of adding to, taking from, putting together, taking apart, and comparing, with unknowns in all positions, e.g., by using objects, drawings, and equations with a symbol for the unknown number to represent the problem.
CCSS1.OA.B.4
Understand subtraction as an unknown-addend problem. For example, subtract 10 – 8 by finding the number that makes 10 when added to 8.
CCSS1.OA.C.5
Relate counting to addition and subtraction (e.g., by counting on 2 to add 2).
CCSS1.OA.C.6
Add and subtract within 20, demonstrating fluency for addition and subtraction within 10. Use strategies such as counting on; making ten (e.g., 8 + 6 = 8 + 2 + 4 = 10 + 4 = 14); decomposing a number leading to a ten (e.g., 13 - 4 = 13 - 3 - 1 = 10 - 1 = 9); using the relationship between addition and subtraction (e.g., knowing that 8 + 4 = 12, one knows 12 - 8 = 4); and creating equivalent but easier or known sums (e.g., adding 6 + 7 by creating the known equivalent 6 + 6 + 1 = 12 + 1 = 13).
Reviews
Questions & Answers
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